(1/64)^(0.5x-3)=89x-2

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Solution for (1/64)^(0.5x-3)=89x-2 equation: 



(1/64)^(0.5x-3)=89x-2

We move all terms to the left:

(1/64)^(0.5x-3)-(89x-2)=0



Domain of the equation: 64)^(0.5x-3)!=0

x∈R



We add all the numbers together, and all the variables

(+1/64)^(0.5x-3)-(89x-2)=0

We get rid of parentheses

(+1/64)^(0.5x-3)-89x+2=0

We multiply all the terms by the denominator


(+1-89x*64)^(0.5x-3)+2*64)^(0.5x-3)=0

We add all the numbers together, and all the variables

(-89x*64+1)^(0.5x-3)+2*64)^(0.5x-3)=0

We add all the numbers together, and all the variables

(-89x*64+1)^(0.5x-3)+2*64)^(0.5x=0

Wy multiply elements

(-89x*64+1)^(0.5x-3)+128x=0

We add all the numbers together, and all the variables

128x+(-89x*64+1)^(0.5x-3)=0

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